well yeah, that's probably what he had in mind but..... mine is cleverer. And besides this hypothetical matchstick equation would look better if the creator had broken a matchstick in half to make the +, thus making my solution only require the movement of 1/2 a matchstick .
Correct! The question is worded to seems like you need to move a matchstick, but you don't need to.
Scores: Andrew: 9 (+2) Don.Gato: 7 MegaMarbler: 1
Puzzle 10 - Train Station Conundrum - Hard
It takes 15 minutes to travel from Station A to Station B. A -> B 15 minutes It takes 5 minutes to travel from Station B to Station C. B -> C 5 minutes It takes 10 minutes to travel from Station C to Station D. C -> D 10 minutes However, it doesn't take 30 minutes for a train to travel from Station A to D. How long would it take, using the information above, and that the railway is a straight line with no branches, for a train to travel from Station A to D?
'The future will be better tommorow' - Dan Quayle 'For NASA, Space is still a high priority.' - Dan Quayle... again.
Meh unless I am missing something, this riddle is impossible. It could be said what the difference is LIKELY to be, but that isn't the question. Of course the obvious answer to that would appear to be 3, but since we are dealing with probability now it must be pointed out that despite the distribution of colored cards being 50-50, the probability of the color distribution staying the same when the randomly ordered deck is split randomly in two is quite low.
I just figured it out. 3 is after all the correct answer. I was mistakenly assuming that the actual numbers of red/black cards would effect the answer.
The number of red cards in the left pile, and the number of black cards in the right pile can be determined in the following equation. Basically, the total number of red cards (26) minus the number of red cards in the left pile (x) tells you how many red cards are in the right pile. By subtracting that number from the total number of cards in that pile (29) you determine the number of black cards in the right pile.
29 - (26 - x) = y
Now we could try it for every possible value of x, there's only 24 possibilities anyway. Or we could use more math and simplify the equation. (excuse the inefficient and generally crappy way I did this, I haven't done anything like this in years. I was improvising)
29 - (26 - x) = y
29 = y + (26 - x)
- y + 29 = 26 - x
- y = - 3 - x
y = x + 3
.... and we get this: y - x = 3
which proves that the difference between black cards in the right pile (y) and red cards in the left pile (x) is = to 3.
In other words I greatly overcomplicated matters, and Andrew was right.